Statistical analysis exam 6 | Algebra homework help
The data set represents the income levels of the members of a country club. Estimate the probability that a randomly selected member earns at least $98,000.
112,000 126,000 90,000 133,000 94,000 112,000 98,000 82,000 147,000 182,000 86,000 105,000
140,000 94,000 126,000 119,000 98,000 154,000 78,000 119,000
A. 0.4 |
|
B. 0.6 |
|
C. 0.66 |
|
D. 0.7 |
Question 13 of 40 |
2.5 Points |
Question 14 of 40 |
2.5 Points |
The distribution of B.A. degrees conferred by a local college is listed below, by major.
Major Frequency
English 2073
Mathematics 2164
Chemistry 318
Physics 856
Liberal Arts 1358
Business 1676
Engineering 868
9313
What is the probability that a randomly selected degree is not in Business?
A. 0.7800 |
|
B. 0.8200 |
|
C. 0.8300 |
|
D. 0.9200 |
Question 15 of 40 |
2.5 Points |
A. The improvement was due to the fact that there were more weeds in one study. |
|
B. The probability that the difference was due to chance alone is greater than 0.05. |
|
C. The probability that one weed killer performed better by chance alone is less than 0.05. |
|
D. There is not enough information to make any conclusion. |
Question 16 of 40 |
2.5 Points |
A. 12 |
|
B. 22 |
|
C. 24 |
|
D. 26 |
Question 17 of 40 |
2.5 Points |
A. 1/2 |
|
B. 2/3 |
|
C. 3/4 |
|
D. 4/9 |
Question 18 of 40 |
2.5 Points |
A. 1/24 |
|
B. 1/46 |
|
C. 1/32 |
|
D. 1/18 |
Question 19 of 40 |
2.5 Points |
A. 0.384 |
|
B. 0.380 |
|
C. 0.373 |
|
D. 0.370 |
Question 20 of 40 |
2.5 Points |
A. The Monday series is closer because 1/6 is closer to 1/2 than is 1/8. |
|
B. The Monday series is closer because 6/12 is closer to 0.5 than is 8/18. |
|
C. The Tuesday series is closer because the 13/18 is closer to 0.5 than is 9/12. |
|
D. The series closest to the theoretical 50/50 cannot be determined without knowing the number of odds and evens in each series. |
Question 21 of 40 |
2.5 Points |
Eleven female college students are selected at random and asked their heights. The heights (in inches) are as follows:
67, 59, 64, 69, 65, 65, 66, 64, 62, 64, 62
Estimate the mean height of all female students at this college. Round your answer to the nearest tenth of an inch if necessary.
A. It is not possible to estimate the population mean from this sample data |
|
B. 64.3 inches |
|
C. 64.9 inches |
|
D. 63.7 inches |
Question 22 of 40 |
2.5 Points |
Suggest the cause of the correlation among the data.
The graph shows strength of coffee (y) and number of scoops used to make 10 cups of coffee (x). Identify the probable cause of the correlation.
A.
The variation in the x variable is a direct cause of the variation in |
|
B. There is no correlation between the variables. |
|
C. The correlation is due to a common underlying cause. |
|
D. The correlation between the variables is coincidental. |
Question 23 of 40 |
2.5 Points |
The scatter plot and best-fit line show the relation among the number of cars waiting by a school (y) and the amount of time after the end of classes (x) in arbitrary units. The correlation coefficient is -0.55. Determine the amount of variation in the number of cars not explained by the variation time after school.
A. 55% |
|
B. 70% |
|
C. 30% |
|
D. 45% |
Question 24 of 40 |
2.5 Points |
Select the best estimate of the correlation coefficient for the data depicted in the scatter diagram.
A. -0.9 |
|
B. 0.9 |
|
C. 0.5 |
|
D. -0.5 |
Question 25 of 40 |
2.5 Points |
A. 7,000 |
|
B. 8,000 |
|
C. 9,000 |
|
D. 10,000 |
Question 26 of 40 |
2.5 Points |
Which point below would be an outlier if it were on the following graph?
A. (25, 20) |
|
B. (5, 12) |
|
C. (7, 5) |
|
D. (5, 3) |
Question 27 of 40 |
2.5 Points |
A. 0.2323 to 0.3075 |
|
B. 0.2325 to 0.3075 |
|
C. 0.2325 to 0.3185 |
|
D. 0.2323 to 0.3185 |
Question 28 of 40 |
2.5 Points |
A. 0.8 standard deviations above the mean |
|
B. 0.8 standard deviations below the mean |
|
C. 7.3 standard deviations below the mean |
|
D. 207 standard deviations below the mean |
Question 29 of 40 |
2.5 Points |
The graph shows a measure of fitness (y) and miles walked weekly. Identify the probable cause of the correlation.
A. The correlation is coincidental. |
|
B. There is a common underlying cause of the correlation. |
|
C. There is no correlation between the variables. |
|
D. Walking is a direct cause of the fitness. |
Question 30 of 40 |
2.5 Points |
A random sample of 30 households was selected from a particular neighborhood. The number of cars for each household is shown below. Estimate the mean number of cars per household for the population of households in this neighborhood. Give the 95% confidence interval.
A. 1.14 to 1.88 |
|
B. 1.12 to 1.88 |
|
C. 1.12 to 1.98 |
|
D. 1.14 to 1.98 |
Question 31 of 40 |
2.5 Points |
The scatter plot and best-fit line show the relation among the data for the price of a stock (y) and employment (x) in arbitrary units. The correlation coefficient is 0.8. Predict the stock price for an employment value of 6.
A. 8.8 |
|
B. 6.2 |
|
C. 8.2 |
|
D. None of the values are correct |
Question 32 of 40 |
2.5 Points |
A. 0.8849 |
|
B. 0.5 |
|
C. 0.1131 |
|
D. 0.1151 |
Question 33 of 40 |
2.5 Points |
A sample of nine students is selected from among the students taking a particular exam. The nine students were asked how much time they had spent studying for the exam and the responses (in hours) were as follows:
18, 7, 10, 13, 12, 16, 5, 20, 21
Estimate the mean study time of all students taking the exam. Round your answer to the nearest tenth of an hour if necessary.
A. 13 hours |
|
B. 12.2 hours |
|
C. 13.6 hours |
|
D. It is not possible to estimate the population mean from this sample data |
Question 34 of 40 |
2.5 Points |
Among a random sample of 500 college students, the mean number of hours worked per week at non-college related jobs is 14.6. This mean lies 0.4 standard deviations below the mean of the sampling distribution. If a second sample of 500 students is selected, what is the probability that for the second sample, the mean number of hours worked will be less than 14.6?
A. 0.5 |
|
B. 0.6179 |
|
C. 0.6554 |
|
D. 0.3446 |
Question 35 of 40 |
2.5 Points |
A. 0.8932 |
|
B. 0.8920 |
|
C. 0.9032 |
|
D. 0.9048 |
Question 36 of 40 |
2.5 Points |
A. 0.0432 |
|
B. 0.0434 |
|
C. 0.0425 |
|
D. 0.0427 |
Question 37 of 40 |
2.5 Points |
A. 0.14 |
|
B. 0.26 |
|
C. 211 |
|
D. 0.23 |
Question 38 of 40 |
2.5 Points |
A. The reported margin of error is consistent with the sample size. |
|
B. There is not enough information to determine whether the margin of error is consistent with the sample size. |
|
C. The sample size is too small to achieve the stated margin of error. |
|
D. For the given sample size, the margin of error should be smaller than stated. |
Question 39 of 40 |
2.5 Points |
A. 274 |
|
B. 284 |
|
C. 264 |
|
D. 272 |
Question 40 of 40 |
2.5 Points |
Write possible coordinates for the single outlier such that it would no longer be an outlier.
A. (23, 18) |
|
B. (20, 5) |
|
C. (15, 15) |
|
D. (12, 15) |